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Solve. 6 – 3x = 4(3 – x) – 6 A. 6 B. –6 C. 0 D. all real numbers
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wrong x = 0...
6-3x=12-4x-6 got dis step?
now we have to bring x terms to one side nd constant no.s should be moved to the other side
ok
6–3x=4(3–x)–6 lets first distribute 4 over the parantheses so 6-3x=12-4x-6 now simplify the right side 6-3x=6-4x now add 4x to both sides to move the variables to the left 6+x=6 substract 6 from both sides x=0
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Give medal to @insanitycat she did the real work and showed you how to do it... thx!!!
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