Question

find an equation of a line passing through the origin and parallel to the line passing through the points (2,8), (4,12)

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(2\quad ,&8)\quad &(4\quad ,&12)
\end{array}
\\\quad \\

slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}
\\ \quad \\

y-y_1=m(x-x_1)\quad \textit{plug in your values and solve for "y"}\)

Answer 2

i need a tutor this time around write the equation 5x-6y-12=0 in the slope intercept form and then find the slope and y intercept of the corresponding line