Question

The area of a rectangle is 63yd^2, and the length of the rectangle is 5yd more than twice the width. Find the dimensions of the rectangle.

Answer 1

Length and Width

Answer 2

since the length is L = 2W +5, and W = W
then W * (2W +5) = 63

Answer 3

which simplifies to 2w^2 +5w = 63 and that to

2w^2 + 5w -63 = 0 solve for w and pick only the positive number that's your answer