Ask your own question, for FREE!
Physics 5 Online
OpenStudy (anonymous):

A massless spring of force constant 19 N/m hangs vertically. a body of mass 0.20kg is attached to its free end and then released. assume that the spring was unstretched before the body was released. how far below the initial position the body descends.

OpenStudy (anonymous):

use the spring constant formula(Hooks Law): \[k = \frac{F}{x}\] where k = 19 N/m, F = Fg = mg, find x

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
17 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
20 hours ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Arizona: does anyone know the percentage rate of 30,000 and 40,000
1 week ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!