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find the width of a rectangle if the diagonal is 18, and the length is 8
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think of the diagonal separating the rectangle into right triangles. you have the hypotenuse (diagonal) and a leg (the length) to find the with use pythagoreon theorem 8^2+b^2=18^2 solve for b
would be equal b=388
don't forget to un square root it
may i get an example how to do this work ?
64+b^2=324 b^2=260 b= sqrt{260}
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how you get 260 on the example did u divide something
wait if u subtract that wouldnt u get -260
324-64=260
thank u caleb
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