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Deriv of r= 8^-t ?
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is it -8^-t?
No. Don't forget the chain rule. :D (Or just pull it off a table because it's simple)
what is it then? ): lol
\[-8^{-t}\ln 8\] You can prove that by rewriting it in terms of \(e\) but it's easy enough to just remember, too.
You can probably generalize it as \(\frac{d}{dx}n^x = \frac{x}{|x|}n^x\ln n\) but I haven't thought that through 100%
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