Let f(x) = \sqrt{20 - x} and g(x) = x^2 - x.
Then the domain of f\circ g is equal to [a,b] for

Question

Let f(x) = \sqrt{20 - x} and g(x) = x^2 - x.
Then the domain of f\circ g is equal to [a,b] for

anonymous · Answer

$$(f\circ g)(x) = \sqrt{20-\left( x^2 - x \right)}\Rightarrow \left[ 20-\left( x^2 - x \right) \right] \ge 0$$

anonymous · Answer

I need in [a,b], infinity is not defined

anonymous · Answer

you just looking for an answer?

anonymous · Answer

yeah I am just looking for an answer because the answers I keep getting are wrong.

anonymous · Answer

can you solve the last inequality I wrote?

anonymous · Answer

Yes I got it now THANK YOU!

anonymous · Answer

you're welocme!

anonymous · Answer

welcome

goformit100 · Answer

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