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Let A be the set {1,2,3,4} which ordered pairs are in the relation R={(a,b) such that a divides b }? it's solved here but why there's no R= {3,1} or {3,2} ? and some other sets ? 3/2 does not give a 0 , so what's going on here ?
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divides means goes in to with no remainder
if a|b, then for some integer k, b = ak
it doesn't mean "you can divide it"
ah , thank you ^^
i think this is saying you are stuck in "posting" mode ....
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Because I can't thank you enough !
:) good luck
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