Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

Answer 1

first we have to find the slope of the line given. To do this, we will put it in y = mx + b form and m is the slope.
4x - 3y = -12 (subtract 4x from both sides)
-3y = -4x - 12 (now divide both sides by -3)
y = -4/-3x - 12/-3
y = 4/3x + 4
slope is 4/3.
Parallel lines have the same slope.

Now we will use y = mx + b
slope(m) = 4/3
(-3,4) x = -3 and y = 4
now lets sub...
y = mx + b
4 = 4/3(-3) + b
4 = - 12/3 + b
4 = - 4 + b
4 + 4 = b
8 = b

your parallel line is : y = 4/3x + 8