Question

write a program that gets an integer value from the user and
calculates the following:
1) additive persistence and the corresponding additive root
2) multiplicative persistence and the corresponding multiplicative root
You will continue to do so until the user quits.

Answer 1

1. The beginning integer is 1234
2. Sum its digits is 1+2+3+4 = 10
3. The integer is now 10
4. The sum of its digits is 1 + 0 = 1
5. The integer is 1. When the value reaches a single digit, we are finished.

Answer 2

Hint: use the modulo operator.

Answer 3

which language is this ?

Answer 4

how is it ?

Answer 5

What?

Answer 6

how can I apply it with different functions I got this big program but how can I generalize it
n1=0
n2=0
n3=0
n4=0
s=0
n=int(input('input is your number:'))
n1=n%10
n2=(n%100-n1)/10
n3=(n%1000-n%100)/100
n4=(n%10000-n%1000)/1000
s=n1+n2+n3+n4
p=n1*n2*n3*n4
if s%10==s:
print('the sum of the digits is :',s,'and the additive persistence is:1')
else:
n1=s%10
n2=(s%100-n1)/10
n3=(s%1000-s%100)/100
n4=(s%10000-s%1000)/1000
s=n1+n2
p=n1*n2*n3
if p%100==s
print('the product of the digits is :',p,'and the multiplicative persistence is:1')

Answer 7

use loops

Answer 8

how

Answer 9

can u show me how @dust7

Answer 10

I'm not sure I understand your problem specification, could you be more clear about it?
- take input from user
- if input is 1, return
-else... (add digits?)

Answer 11

ok I've don it thanks ..