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Mathematics 8 Online
OpenStudy (anonymous):

Am I wrong?

OpenStudy (anonymous):

Since YouTube first became available to the public in mid-2005, the rate at which video has been uploaded to the site can be approximated by: v(t) = 525,600(0.42t^2 + 2.7t − 1) hours of video per year (0.5 ≤ t ≤ 7), where t is time in years since the start of 2005.† Use a definite integral to estimate the total number of hours of video uploaded from the start of 2006 to the start of 2012. (Round your answer to the nearest million hours of video.)

OpenStudy (anonymous):

I have 5.6701 x 10^7

OpenStudy (anonymous):

please help, it's my last question and it's due in 40 mins

OpenStudy (anonymous):

Well if you used\[\int\limits_{6}^{7} 525600(0.42t ^{2}+2.7t-1)\] it should be right

OpenStudy (anonymous):

which I did, how do I take my answer and round it to the nearest million... and wait, from 6 to 7? why not 1 to 7 (which is what I used to get my answer)?

OpenStudy (anonymous):

Oh yea my bad it is 1 to 7

OpenStudy (anonymous):

So then, you should have 56,071,008 or 5.6071 x 10^7 but rounding to the nearest million would just be 56,000,000.

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