Question

help!

Answer 1

A line passes through the points (-3,-4) and (5,12). What is the equation of the line that is perpendicular to this line and passes trough the midpoint of the two points?

Answer 2

@Directrix I have the answer, I just want to know if its right

Answer 3

Is the answer y=-1/8+20 ?

Answer 4

m=y2-y1 => m=-4-12/-3-5 = -16/-8=2
right ?;)

Answer 5

m=y2-y1/x2-x1
!!!
@ineedhelp10

Answer 6

Your supposed to subtract 12--4 and then subtract 5-3 which will actually equal to 8 as the slope

Answer 7

!
look :
(-3,-4) and (5,12)
x1 y1 x2 y2
12-(-4)/5-(-3)=16/2 = 8
you was right !
sorry !:p
So ... you get slope -1/8 ... right ?!;)

Answer 8

then :
y2-y1=m(x2-x)

Answer 9

yeah i do get -1/8

Answer 10

Then m=20

Answer 11

no prob !:P
non onon oon nono ono noon ! we got m = 8 . so m always is 8
therefore :
12-y=8(5-x)
12-y=40-8x
-y=40-8x-12
-y=-8x + 28
y=8x-28
m=8 now too !;)
Got it ?:)

Answer 12

I dpnt understand how in the 3rd line you switch -12 to the other side

Answer 13

@E.ali

Answer 14

there is not 3rd line !
tell me first what was the slope ?:)

Answer 15

oh wait nvm! i figured it out!

Answer 16

so after doing that what will we do?

Answer 17

look you said m ( slope ) is 8 .
you found that ... !
ok ?

Answer 18

hmnm

Answer 19

so . if we want find an equation for a line use this :
y2-y=m(x2-x)
ok ?

Answer 20

ok

Answer 21

so get numbers in m and y2 and x2 .what will we have ?

Answer 22

y=8x-28

Answer 23

you get it ?!

Answer 24

yeah. so is that the final answer then?

Answer 25

yea !

Answer 26

why you said did nt get it ?
i think you re smart !;)

Answer 27

thank you so much, you made my day=D

Answer 28

you re welcome ;)
i do nothing !!! you knew thew answer ... ;)

Answer 29

And how can I make sure my answer is correct?

Answer 30

you can draw that line !;)

Answer 31

okay. thank you so much:)

Answer 32

:D