Question

Can anyone help me with this one ? find the center, verticles, and foci of this ellipse.
2.(x+6)^2/12+(Y-4)^2/16=1
@ikram002p @dan815 @86camaro @divu.mkr

Answer 1

start wid
\[\frac{ x^2 }{ 6 }+\frac{ y^2 }{16 }\]

Answer 2

then the center point is (-6,4) so shift that ellips from (0,0 ) to this point.

Answer 3

the verticles is (+-4sqrt6)

Answer 4

@ikram002p im confused . Whats the verticles? & whats the foci?

Answer 5

for
x^2/6+y^2/16=1

Answer 6

thanks