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Mathematics 14 Online
OpenStudy (anonymous):

Find a cubic function with the given zeros. -2, 5, -6 f(x) = x3 + 3x2 + 28x - 60 f(x) = x3 - 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x + 60

hartnn (hartnn):

if 'a' is a zero of f(x), then (x-a) is one factor so when '5' is a zero , what is the factor ?

OpenStudy (anonymous):

5- a

hartnn (hartnn):

you put 5 instead of 'x' ? there 'a' was a zero, here '5' is a zero, so put a=5 instead

OpenStudy (anonymous):

ohhhh okay .

OpenStudy (anonymous):

so x - 5

hartnn (hartnn):

yes, correct :) what about -2 as a zero ? factor is ?

OpenStudy (anonymous):

x + 2

hartnn (hartnn):

yes! so i guess you have already figured out that x+6 is also a factor, so your f(x) = (x+2)(x-5)(x+6) can you foil ?

OpenStudy (anonymous):

mmm , kinda , hang on and i'll try (:

OpenStudy (anonymous):

-60 + -28x + 3x2 + x3

hartnn (hartnn):

thats correct! good work :D

hartnn (hartnn):

sorry for late reply, my ninternet is acting weird :P

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