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Find a cubic function with the given zeros. -2, 5, -6 f(x) = x3 + 3x2 + 28x - 60 f(x) = x3 - 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x - 60 f(x) = x3 + 3x2 - 28x + 60
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if 'a' is a zero of f(x), then (x-a) is one factor so when '5' is a zero , what is the factor ?
5- a
you put 5 instead of 'x' ? there 'a' was a zero, here '5' is a zero, so put a=5 instead
ohhhh okay .
so x - 5
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yes, correct :) what about -2 as a zero ? factor is ?
x + 2
yes! so i guess you have already figured out that x+6 is also a factor, so your f(x) = (x+2)(x-5)(x+6) can you foil ?
mmm , kinda , hang on and i'll try (:
-60 + -28x + 3x2 + x3
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thats correct! good work :D
sorry for late reply, my ninternet is acting weird :P
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