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What is the solution of log2x − 4 16 = 4? x = −3 x = 3 x = −2 x = 2
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\[\log_{2x-4} 16=4\] I keep getting x=1/2
first get the log by itself on the left side
do i just go about solving 2x-4? 2x+4 - 4+4 2x-0 2/2? I'm not sure lol
no no solve just like you would algebraically. so add 416 to both sides
No, I wrote it underneath my post. It's log(2x-4) 16=4
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It isn't 416............................
x=3
Thanks.. are you sure?
yes sir.
I'm a girl oo"
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yes ma'am
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