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OpenStudy (abb0t):
Answer is \(C\)
OpenStudy (anonymous):
OpenStudy (anonymous):
haha XD
OpenStudy (haseeb96):
what we find here?
OpenStudy (idku):
do still need help on this?
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OpenStudy (anonymous):
Yeah, I still need this. (Sorry on the late responce. Computer issues)
We're supposed to "Use graphing to find the solutions to the system of equations."
I can post the graphs if needed.
OpenStudy (idku):
you guys are typing for like an hour....
OpenStudy (anonymous):
My computer is being pretty laggy, haha.
OpenStudy (haseeb96):
y-x^2+2x=-4 ....eq: 1
y+x=2...... eq: 2
first we take eq : 2
y=x-2
put this value in eq : 1
x-2-x^2+2x=-4
x=-4+x^2+2
x^2-x-2=0
x^2-x+2x-2=0
x(x-1)+2(x-1)=0
(x+2)(x-1)=0
either
x=-2 or x=1
now put x=-2 in eq:3 or x=1 in eq 3
y=-2-1 or y=1-1
y=-3 or y=0
(-2,-3), (1,0)
this is the answer