Question

find the inverse of the function
f(x)=x^2-1/x^2+1

Answer 1

\(\bf f(x)=y=\cfrac{x^2-1}{x^2+1}\qquad \textit{inverse would be}\implies x=\cfrac{y^2-1}{y^2+1}\)

however, do you see anything amiss in this graph? http://www.wolframalpha.com/input/?i=x%3D%28y%5E2%E2%88%921%29%2F%28y%5E2%2B1%29&dataset=