A triangle has a base that is increasing at a rate of 3 cm/sec and a height that is decreasing at a rate of 2 cm/sec. Find the rate of change of the area of the triangle when the height is 10 cm and the area is 40 cm .

Question

A triangle has a base that is increasing at a rate of 3 cm/sec and a height that is decreasing at a rate of 2 cm/sec.  Find the rate of change of the area of the triangle when the height is 10 cm and the area is 40 cm  .

anonymous · Answer

A = (1/2)BH

differentiate both sides, you get dA/dt = .....

just substitute dB/dt = 3, dH/dt = -2,.....