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find the solutions to the system y=x^2+8x+2 y=x+4 a. (-2,-10) and (1,11) b. (2,10) and (-1,-11) c.(-2,-34) and (1,11) d.No solutions
using 'y=x+4' you can substitute x+4 into y=x^2+8x+2 for y and solve for x.
i dont understand..
What he means is that in the first equation replace "y" with "x+4"!
So x+4=x^2+8x+2?
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Exactly!
subtract 2 from 4 and get x+2=x^2+8x?
i would subtract x from both sides and then subtract 4 from both sides. tell me what is the result of your subtractions after you do this.
Whats x- x^2?
I am going back on the x+4=x^2+8x+2
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x+4- (x+4) =x^2+8x+2 - (x+4)
im lost. now.
x+4-(x+4)= x^2+8x+2-(x+4) IS 0=x^2+7x-2.
Is it (-2,-10) and (1,11)
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