**MEDAL FOR THE BEST ANSWER!!**
Input in standard form the equation of the given line. The line that passes through (-1, -3) and (2, 1)
find the slope first... i think now you know the steps ?
(1- (-3)) / ( 2 - (-1)) = 4/3?
m = 4/3 yes correct
x1 = 2 y1 = 1 y-y1 = m (x-x1)
Where did you get the 2 and 1 from?
point ---->" (2, 1)"
Ohh! Okay so y - 1 = 4/3 (x - 2)
yes, bring it in the form ax+by =c a as positive
So multiply each side by 3 and that brings us to 3y-3 = 4x - 6. Then we add 3 to both sides making it 3y = 4x - 3. Then we want to isolate c so we subtract 4x by both sides making it -4x + 3y = -3. Right? Then aren't we supposed to make the -4x positive?
4 (x-2) = 4x-8
Ohh oops I multiplied the -2 by 3 as well. So then it's 3y = 4x - 5, right?
yes now subtract 3y from both sides ...
So -4x = -3y - 5?
why did u bring 4x on left ? we need to keep a as positive so 0 = 4x-3y -5 got this ? now add 5 on both sides
Okay so 5 = 4x - 3y.
thats it!
or 4x-3y = 5
Awesome! Thank you so much! I understand it all so much better! You've really helped me a lot!
always happy to help :) welcome ^_^
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