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OpenStudy (anonymous):
OpenStudy (ranga):
I can help guide you in finding the right answer if you wish.
Can you tell me the slope of the line in the problem? y = -10x + 1
OpenStudy (anonymous):
-10
OpenStudy (ranga):
Yes. The slope of the perpendicular line will be the negative reciprocal of the slope you just found. So what will be the slope of the perpendicular line?
OpenStudy (anonymous):
-1/10?
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OpenStudy (ranga):
It should be the negative reciprocal.
OpenStudy (anonymous):
1/10
OpenStudy (ranga):
Yes. Slope = 1/10.
The equation of a line in slope intercept form is: y = mx + b
put the value of m
y = 1/10x + b
We are given that the perpendicular line passes through (5,7)
Put x = 5 and y = 7 and solve for b.
OpenStudy (anonymous):
b=13/2
OpenStudy (ranga):
Yes. So the equation of the perpendicular line in slope-intercept form is:
y = 1/10x + 13/2
Put this in standard form. Standard form of a line looks like: Ax + By = C
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OpenStudy (anonymous):
-1/10x+y=13/2
OpenStudy (ranga):
Yes. You can multiply throughout by -1 just to make the coefficient of x positive.
OpenStudy (anonymous):
so 1/10x-y=-13/2?
OpenStudy (ranga):
Yes. Does it agree with any of the choices?
OpenStudy (anonymous):
yes. its a.
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OpenStudy (ranga):
Yes.
OpenStudy (anonymous):
thank you
OpenStudy (ranga):
you are welcome. you pretty much did the whole thing yourself.