Question

The word "independent" is spelled out on index cards, one letter
per card. Ken randomly selects a card and does not replace it,
and then Barb randomly selects a card. What is the probability
that they both get a card with an "e" written on it?

A. 3/55
B. 9/121
C. 26/55
D. 6/11

I got A!

Answer 1

There are 3 of the letter E in the word independent.

There are 11 letters in the word "independent."

Answer 2

The probabilty that Ken draws the letter E = the number of Es divided by the number of letters. That would be 3/11.

The probability that Barb draws the letter E = the number of remaining Es divided by the number of remaining letters. That would be 2/10.

P(Ken E and Barb E) = 3/11 * 2/10 = ?

Answer 3

>>> I got A! I agree with that, @katlin95