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Mathematics 21 Online
OpenStudy (amtran_bus):

Proportionality Need help with part C

OpenStudy (amtran_bus):

hartnn (hartnn):

use d = 0.62 * 10^9, and the k value you got , plug it into \(T^2=kd^3\) only T is unknown

OpenStudy (amtran_bus):

Then convert to years?

hartnn (hartnn):

yes, you will get answer in days divide by 365 to convert it into years

OpenStudy (amtran_bus):

So it is T^2 = 1.656x10^-19 * (0.62x10^9)^3 I got 198.663 so divided by 365 = .544?

OpenStudy (amtran_bus):

Nope, something is wrong there.

OpenStudy (amtran_bus):

But it says1.656x10^-19 on part B.

hartnn (hartnn):

yeah, and that divided by 365 will give http://www.wolframalpha.com/input/?i=%5B1.656*10%5E-19+*+%280.62*10%5E9%29%5E3%5D%2F365

hartnn (hartnn):

so many years :O

OpenStudy (amtran_bus):

Thank you. Thats what I was thinking!!!!!

hartnn (hartnn):

welcome ^_^

OpenStudy (amtran_bus):

Can you show my part c here?

OpenStudy (amtran_bus):

Is that all? Thanks phi.

hartnn (hartnn):

yep, thats it

OpenStudy (amtran_bus):

So just 6*14?

OpenStudy (amtran_bus):

OpenStudy (phi):

make sure the question does not change the x distance

OpenStudy (amtran_bus):

OpenStudy (phi):

oops, the distance x is the difference between unstretched 11 cm and 14 cm so use x=3

hartnn (hartnn):

yeah, 11 to 16 is 5 so, 11 to 14 will be 3 x=3

OpenStudy (amtran_bus):

I understand now. Thanks.

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