limit of the funtion :-
{[(2^n)+ 1][(7^n)+(10^n)]}^(1/n)
as n tends to zero

Question

limit of the funtion :- 
{[(2^n)+ 1][(7^n)+(10^n)]}^(1/n)
as n tends to zero

anonymous · Answer

$$\lim_{n \rightarrow 0}{[(2^n)+ 1][(7^n)+(10^n)]}^{1/n}$$
The better view

anonymous · Answer

Also try
$$\lim_{n \rightarrow \infty}{[(2^n)+ 1][(7^n)+(10^n)]}^{1/n}$$

math&ing001 · Answer

Try using the logarithmic function Ln

anonymous · Answer

k...then what??

anonymous · Answer

the limit = 20 

do L'Hopital rule! or review the basic concepts of evaluating a limit!

anonymous · Answer

Which sum? the one in which n tends to 0 or n tends to infinity??

dumbcow · Answer

both limits go to infinity http://www.wolframalpha.com/input/?i=lim+%282%5En+%2B1%29%287%5En+%2B10%5En%29%5E%281%2Fn%29+as+n-%3Einfinity http://www.wolframalpha.com/input/?i=lim+%282%5En+%2B1%29%287%5En+%2B10%5En%29%5E%281%2Fn%29+as+n-%3E0

anonymous · Answer

Actually I have got the answers...
as n tends to zero the limit value is 16 and as n tends to infinity the answer is 20.
But how is that calculator showing infinity??

math&ing001 · Answer

Because you're working with discrete numbers and the calculator works with real numbers.

anonymous · Answer

I couldn't get you...