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Calculus1 18 Online
OpenStudy (anonymous):

limit of the funtion :- {[(2^n)+ 1][(7^n)+(10^n)]}^(1/n) as n tends to zero

OpenStudy (anonymous):

\[\lim_{n \rightarrow 0}{[(2^n)+ 1][(7^n)+(10^n)]}^{1/n}\] The better view

OpenStudy (anonymous):

Also try \[\lim_{n \rightarrow \infty}{[(2^n)+ 1][(7^n)+(10^n)]}^{1/n}\]

OpenStudy (math&ing001):

Try using the logarithmic function Ln

OpenStudy (anonymous):

k...then what??

OpenStudy (anonymous):

the limit = 20 do L'Hopital rule! or review the basic concepts of evaluating a limit!

OpenStudy (anonymous):

Which sum? the one in which n tends to 0 or n tends to infinity??

OpenStudy (anonymous):

Actually I have got the answers... as n tends to zero the limit value is 16 and as n tends to infinity the answer is 20. But how is that calculator showing infinity??

OpenStudy (math&ing001):

Because you're working with discrete numbers and the calculator works with real numbers.

OpenStudy (anonymous):

I couldn't get you...

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