2 sin^2 theta= sin theta. Find 4 solutions please!
first write it as 2 sin^2 theta - sin theta = 0 now factor left hand side
Not sure how this would factor out
sin theta is common to both terms so take it out and put the rest in parentheses
so it would be 2sin theta(sin theta- sin theta)?
no its sin theta(2 sin theta - 1 ) = 0
you divide 2 sin theta - sin theta by sin theta and the result goes into the parentheses
now when the product of 2 functions = 0 either one of them must = 0 so you have to solve the following 2 equations sin theta = 0 and 2 sin theta - 1 = 0
I get how to solve it now but I am just a little confused on how you came up with the 2 equations from that one equation
consider a simpler example x(x - 2) = 0 x times (x - 2) = 0 for the result to be zero either x = 0 or (x - 2) = 0
any number times zero equals zero
Spot on. Perfect explanation! thank you for the help!
yw
Join our real-time social learning platform and learn together with your friends!