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6 white balls ,4 red balls ,9 black balls .three balls are drawn at random (with replacdment ) find probability that one ball is red
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OK add them together and you get 19
Total number of ways =969
so it could be 6 /19 because you have a likely chance of 6 to pick a red ball because there are 6 red balls out of 19
i am pretty sure that could be the answer
I guess it should be 4c1+15c2
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Anyone please its urgent
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