Question

Derivative of y=sin2t

Answer 1

so you just need to use the chain rule!

let 2t=u
so y=sin(u) u=2t
dy/du=? du/dt=?

then dy/dt=dy/du * du/dt

Answer 2

or in simple terms
1)differentiate the brackets
2) differentiate the function

multiply them together

Answer 3

Thanks, have you got a maths degree

Answer 4

I hopefully will have in a few months!