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The equation, in general form, of the line that passes through the point (2,9) and is perpendicular to the line 4 x + 9 y + 1 = 0 is Ax + By + C = 0, where A = B = C =
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can you find slope of 4 x + 9 y + 1 = 0 ?
ya i know how to fine the slop
so whats the slope of that line ?
isent it -4/9
correct! now perpendicular line have product of slopes = -1
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so, m * (-4/9) = -1 m=... ?
9/4?
correct! m = 9/4 x1 =2 y1 =9 can you find the equation ?
y-y1 = m (x-x1) slope point form
it would be Y=9/4x+9/2
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yes, to eliminate the fraction, multiply 4 on both sides
that would make it 4y=9x+18
oh i got it thank you
correct now to get that form, just subtract 4y from both isdes... ohh, welcome ^_^
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