The equation, in general form, of the line that passes through the point (2,9) and is perpendicular to the line 4 x + 9 y + 1 = 0 is Ax + By + C = 0, where
A =
B =
C =

Question

The equation, in general form, of the line that passes through the point (2,9) and is perpendicular to the line 4 x + 9 y + 1 = 0 is Ax + By + C = 0, where 
A =  
B =  
C =

hartnn · Answer

can you find slope of 4 x + 9 y + 1 = 0 ?

anonymous · Answer

ya i know how to fine the slop

hartnn · Answer

so whats the slope of that line ?

anonymous · Answer

isent it -4/9

hartnn · Answer

correct!
now perpendicular line have product of slopes = -1

hartnn · Answer

so, 
m * (-4/9) = -1 
m=... ?

anonymous · Answer

9/4?

hartnn · Answer

correct! 
m = 9/4 
x1 =2
y1 =9
can you find the equation ?

hartnn · Answer

y-y1 = m (x-x1)
slope point form

anonymous · Answer

it would be Y=9/4x+9/2

hartnn · Answer

yes, 
to eliminate the fraction, multiply 4 on both sides

anonymous · Answer

that would make it 4y=9x+18

anonymous · Answer

oh i got it thank you

hartnn · Answer

correct
now to get that form, just subtract 4y from both isdes...

ohh, welcome ^_^