Question

How do I solve this rational expression?
(2x+3)/(x^2+4x-5) - (4)/(x-1)

Answer 1

factor \(\bf x^2+4x-5\) first

Answer 2

(x+5)(x-1)

Answer 3

Ok now what do I do? @jdoe0001

Answer 4

\(\bf \cfrac{2x+3}{x^2+4x-5}-\cfrac{4}{x-1}\implies \cfrac{2x+3}{(x+5)(x-1)}-\cfrac{4}{x-1}\\ \quad \\ \textit{our LCD will be }(x+5)(x-1)\\ \quad \\
\cfrac{(2x+3)-4(x+5)}{(x+5)(x-1)}\)

Answer 5

\(\bf \cfrac{(2x+3)-4(x+5)}{(x+5)(x-1)}\implies \cfrac{2x+3-4x-20}{(x+5)(x-1)}\implies \cfrac{-2x-17}{(x+5)(x-1)}\)