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Calculate the cross product assuming that u*w = <7,6,-4> (-5u + 3w)*w =<_______>
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do u mean \[\large u\times w=(7,6,-4) \] ?
yes
@ganeshie8 i need help
hint : cross product is distributive
\((-5u + 3w) \times w = -5u \times w + 3w \times w\)
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how do i substitute the values ?
\((-5u + 3w) \times w = -5u \times w + 3w \times w\) \( = -5 u \times w + 3 * 0\) \( = -5 u \times w \)
cross product of same vectors is 0 \(i \times i = 0\)
substitute the given \(u \times w\) value now
=-5<7, 6 -4> =<-35, -30, 20>
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\(\large \color{red}{\checkmark}\)
Thanks alot
np :)
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