Question

Suppose triangle ABC has vertices at A(1, 0), B(10, 0), and C(2, 6). After a 60° counterclockwise rotation about the origin, vertex C' has coordinates (?, 4.73)

Answer 1

I got -4.203

Answer 2

I found a radius from the origin to the point C making an additional line on the already given triangle and then moved that line 60 degrees to the left which is 41.689 degrees past the origin.