Question

Factor completely:40x^2-100x-60

Answer 1

20(2x^2-5x-3)
20(x^2-5x-6)
20(x-6/2)(x+1/2)
20(x-3)(2x+1)
if you don't know this method reply so i can try to solve it in another method

Answer 2

show me another steps

Answer 3

20(2x^2-5x-3)
20(2x(x-3)+1(x-3))
20(x-3)(2x+1) but still it's not understandable so i will show the best solution in the next reply

Answer 4

20(2x^2-5x-3) if you learned to find p's and q's p:3; ±1,±3 q:2; ±1,±2
p/q= ±1,±1/2,±3,±3/2
and you start testing all those positive and negative in synthetic division form until you find which ones gives you the result with remainder 0 ( in that one 3 works)
so the result is 20* (x-3)*(2x+1)

Answer 5

I like the one