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simplify the expression (1+cot theta)(1- cot theta) - csc^2 theta
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Multiple (1 - cot theta)(1+ cot theta) = 1 - cot^2 (theta). sue pythagorean identity that 1+ cot^2(theta) = csc^2 (theta). and you'll be done.
use*
\[(1+\cot \theta)(1-\cot \theta)-\csc ^2\theta =1-\cot ^2\theta-\csc ^2\theta =\] \[1-\cot ^2\theta-(1+\cot ^2\theta)=1-\cot ^2\theta-1-\cot ^2\theta =-2\cot ^2\]
Awesome thank you guys!
yw
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