Question

(x+3)/(2x) * (4x^2)/(2x-1)

Answer 1

\[\Large \frac {(x+3)} {2x} * \frac {4x^2} {(2x-1)}= \] change the order to make it easier\[\Large \frac {(x+3)} {2x-1} * \frac {4x^2} {2x}\]

Answer 2

@Katelynmorris ...?

Answer 3

Not quite sure how to work out the problem from there?

Answer 4

Does the (4x^2)/(2x) equal 2x^2? @agent0smith

Answer 5

what is x^2/x? (it's not x^2)

\[\Large \frac{ x^a }{ x^b}= x^{a-b}\]

Answer 6

x?

Answer 7

@agent0smith

Answer 8

Yes. \[\Large \frac {(x+3)} {2x-1} * 2x\]

Answer 9

(2x^2+6)/(2x-1)?

Answer 10

6x*

Answer 11

yep. \[\Large \frac {2x(x+3)} {2x-1} =\frac {2x^2+6x} {2x-1}\]i think either answer is fine though

Answer 12

Thank you!