Question

Please Assist. Using Logs to solve Exponential Equations
See Attachment

Answer 1

start by dividing 3 on both sides,
what u get ?

Answer 2

3.2^t=27
divide both side by 3
2^t=27/3
2^t=9
taking ln both side
ln(2^t)=ln(9)
t ln(2)=2.197
t(0.301)=2.197
t=2.197/0.301
t=7.298

Answer 3

when I plug ln 2 into my calculator I get 0.693 not 0.301

Answer 4

3.2^t=27
divide both side by 3
2^t=27/3
2^t=9
taking ln both side
ln(2^t)=ln(9)
t ln(2)=2.197
t(0.693)=2.197
t=2.197/0.693
t=3.17

Answer 5

Sorry i forgot

Answer 6

No problem. Thank you!

Answer 7

My Pleasure.