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Mathematics 15 Online
OpenStudy (anonymous):

Please Assist. Using Logs to solve Exponential Equations See Attachment

OpenStudy (anonymous):

OpenStudy (cggurumanjunath):

log(a/b)=log a -log b

OpenStudy (anonymous):

\[\log \frac{ x+14 }{ x }=1 \rightarrow \frac{ x+14 }{ x }=10 \rightarrow x+14=10x \rightarrow x=\frac{ 14 }{ 9 }\]

OpenStudy (anonymous):

thank you!

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