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Mathematics 5 Online
OpenStudy (anonymous):

series question

OpenStudy (anonymous):

Can someone tell me how these two series are the same:\[\sum_{1}^{\infty} \frac{ 3^{k-1}}{ 4^{k+1}}=\sum_{0}^{\infty}(\frac{ 3 }{ 4 })^k\]

OpenStudy (anonymous):

my book says they are the same, but i dont understand how.

OpenStudy (anonymous):

all i see is that they changed the index, it start at 0 instead of 1

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