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does the series converge or diverge? sin(1/n^2) n=1 to infinity
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i know 1/n^2 converges but thats all i got lol
@Easyaspi314
well it is a lot ! think of the comparison test. another big hint : sin(x) <= x for 0<=x<=1
hey sorry i had to go to work...go ahead:) @Coolsector
hey well according to the hint if (1/n^2) is between 0 and 1 (and it is because n goes from 1 to inf) we have sin(1/n^2) < (1/n^2)
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okayy
so done .. cause it is for every term so according to the comparison test ..
it converges correct
yes
beautiful thank you:)
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yw:)
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