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Simplify the exponential expression.
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\[(x ^{3})^{-9}\]
\(\huge (x^m)^n= x^{mn}\)
so you just multiply the exponents
is the ans \[\frac{ 1 }{ x ^{27} }\]
you are \(\huge \color{red}{\checkmark}\)
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or \[-x ^{27}\]
its \(\huge x^{-27} \quad or \quad \dfrac{1}{x^{27}}\)
ook
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