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Mathematics 19 Online
OpenStudy (anonymous):

(x+2)^2-36=0

OpenStudy (anonymous):

difference of squares... let u = x=2 then, \[(x+2)^2-36 \rightarrow u^2-36=(u+6)(u-6)\rightarrow [(x+2)+6][(x=2)-6]\]

OpenStudy (anonymous):

u = x+2

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