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Find the radius of the shown circle with center O given that BC=8 and QO=2
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is there a picture?
|dw:1384127121710:dw|
is it drawn to scale?
No
ok then I think the radius is sqrt of 20 by the Pythagorean theorem
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Where did you get 2^2 and 4^2?
half Bc is 4 since OQ is prependicular it halves BC so in the triangle using pythagoras 4^2 plus 2^2 = 20 so OC the radius is SQRT of 20 which is 2 sqrt{5}
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