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A speeder traveling at 40 m/s passes a stationary police car which can accelerate at 2.5m/s. (A) How long will it take the police car to catch the speeder? (B) At what distance will the speeder get caught? Show Work.
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40t=0.5*(2.5)t^2 Solve for t (time) this is your answer for (a) Once you know what t(time) is; 40*t = distance traveled when police car catches the speeder
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