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Complete the square to solve the equation: x^2+6x=-7
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what is half of \(6\) ?
3
ok good then write \[(x+3)^2=-7+?\] now what is \(3^2\) ?
9
right so it is \[(x+3)^2=-7+9\] or \[(x+3)^2=2\]
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take the square root of both sides, get \[x+3=\pm\sqrt2\] then subtract \(3\)to finish with \[x=-3\pm\sqrt2\]
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