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find sin theta given that cos2 theta =3/5, 3pi/2 <2theta <2pi
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|dw:1384141291781:dw|
Now you have sin^2 theta = 1/5, solve for sin theta, given that theta lies in the 4th quadrant (which means sin is negative there).
so i squre 1/5?
or is 1/5 the answer?
- sqrt(1/5) or - sqrt(5)/5
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sin is negative in 4th quadrant.
|dw:1384141694911:dw| is that how i would answer?
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