Question

the width of a rectangle is 2 centimeters less than one-half its length. if the perimeter is 56 centimeters, find the length and width.

Answer 1

2w+2l=56w=0.5l-2

Answer 2

ignore that

Answer 3

with the equations
2w+2l=56
w-0.5l=-2
create a 2x2 matrix
A=\[\left[\begin{matrix}2 & 2 \\ 1 & -0.5\end{matrix}\right]\]
with an answer matrix of
\[\left(\begin{matrix}56 \\ -2\end{matrix}\right)\]
create two more matrices switching a row of the first matrix with the answer matrix
B=\[\left[\begin{matrix}56 & 2 \\ -2 & -0.5\end{matrix}\right]\] C=\[\left[\begin{matrix}2 & 56 \\ 1 & -2\end{matrix}\right]\]

the w=det(B)/det(A) and l=det(C)/det(A)

w=5(6(-0.5)-(-2)(2))/((2)(-0.5)-2)= -24/-3

w=8

l=((2)(-2)-56))/-3=-60/-3

l=20

Answer 4

I hope I helped

Answer 5

I was actually laughing the whole time I wrote that