genevieve forgot the last two digits of her four digit locker code. If the number is divisible by 5, 6 and 7, what is her locker code?

Question

genevieve forgot the last two digits of her four digit locker code.  If the number is divisible by 5, 6 and 7, what is her locker code?

anonymous · Answer

I think you're meant to have the first two answers also lol..

anonymous · Answer

yeah sorry it was 21??

jack1 · Answer

5 x 6 x 7 = 210
so your number is a multiple of 210 and has 4 digits and begins with 21**... i think?

jack1 · Answer

so whats the first one that comes to mind @BrookieMarton ?

anonymous · Answer

420

anonymous · Answer

The other 2 digits are between 0 and 9, can you repeat?

anonymous · Answer

<3

anonymous · Answer

630, 840,1050

anonymous · Answer

you're missing the hint.. it's a multiple of 210... and it starts with 21..... what could it be???

anonymous · Answer

2100

anonymous · Answer

210

anonymous · Answer

210 is 3 digits, the answer asks for a 4 digit number!

anonymous · Answer

dis u doe

anonymous · Answer

So it's 21_ _
Divisible by 5, 6, and 7

What is the LCD of 5,6, and 7? 5x6x7=210
So 21 _ _ is divisible by 210 

2100 is divisible by 210 which means it's divisible 5,6, and 7

And it's a 4 digit number!

jack1 · Answer

@BrookieMarton 2100 is the answer i believe, multiple of 210 as 10 x 210 = 2100

jack1 · Answer

@lilychong chill girl, it's a help forum hey ;)
not so !   ;D

anonymous · Answer

Thanks so much