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The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units?
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Perimeter = 2(length) + 2(width) so check by substituting.
|dw:1384181287887:dw| perimeter is all the way around
So the equation would be \[24^{2}+11^{2}=70
that is not the right formula, use Easyaspi314 's formula above
oh ok thanks
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the answer would be yes because 2(24)+2(11)=60
right
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