can anyone teach me how to solve an equation contaning three radicals

Question

amistre64 · Answer

a practice problem might be a good thing to work with as well

anonymous · Answer

sir but i dont know how to solve the equatin if it is contaning 3radical i can only solve upto 2

amistre64 · Answer

can you post a problem that has 3radical ?  you mean a cube root?  or 3 square roots?  more context is needed

unklerhaukus · Answer

$$x+\sqrt 2=\sqrt 8+\sqrt {32}\
x=\sqrt {2^2\times2}+\sqrt {2^2\times2^2\times2}-\sqrt2\
x=2\sqrt2+2\times2\sqrt{2}-\sqrt 2\x=(2-2\times2-1)\sqrt2\x=-3\sqrt2$$

anonymous · Answer

no sir i mean 3 square roots

anonymous · Answer

thanks rahuk sir it will help me definetly..

amistre64 · Answer

squareroots, and any other radical, can be considered as an unknown ... a variable.  And they can be treated as such.

If you can present us with a problem to address this would make an abstract idea a bit more concrete to deal with.

amistre64 · Answer

simplifying a radical helps to express all the terms in the setup as "like terms"

unklerhaukus · Answer

$$\sqrt3-\sqrt{27}+\sqrt{90000}\
=\sqrt3-\sqrt{3\times3^2}+\sqrt{3^2}\times\sqrt{100^2}\
=\sqrt3-3\sqrt3+3\times100\
=(1-3)\sqrt3+300\
=300-2\sqrt3$$