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you either have to run long hand or synthetic division ...
let x=2, do we get a zero? or a number?
its the same process as doing it for numbers .... but there is a simpler test let x=2, what does the expression give us?
yes, this tells us that x-2 is not a factor and must have a remainder of -3/(x-2)
id pick the option that has a -3/(x-2) on it .....
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youre welcome a little insight into this wold be: P(x) = (x-2) Q(x) + R P(2) = (2-2) Q(2) + R = -3, R = -3 P(x) = (x-2) Q(x) - 3 , divide off the x-2 \[\frac{P(x)}{(x-2)}=Q(x)-\frac3{(x-2)}\]
regardless of the Q(x), the option we want has to have that -3/(x-2) tacked into it
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