Question

Select the equation of the line that passes through the point (3, -1) and is parallel to the line on the graph.

y = -1

y = 3

y = x -1

y = 3x - 1

Answer 1

http://learn.flvs.net/webdav/assessment_images/educator_algebra1_v17/03_07_quiz/03_07_18.jpg

Answer 2

@PrettyGirlSwag<3

Answer 3

@PrettyGirlSwag<3

Answer 4

If two lines are parallel they will have the same slope. So first you need to find the slope
of the given line 2y - 16x = 3.
.
To find the slope you can work this equation into the slope intercept form of y = mx + b.
When you get it into this form you will know that the slope is m ... the constant that multiplies
the x.
.
Start with:
.
2y - 16x = +3
.
get rid of the -16x on the left side by adding 16x to both sides to get:
.
2y = +16x + 3
.
Solve for y by dividing all terms on both sides by 2 ... the multiplier of y. When you do
this division you get:
.
y = (16/2)*x + 3/2
.
In the first term on the right side the division 16/2 = 8. So the equation becomes:
.
y = 8x + 3/2
.
Note that this is now in the slope intercept form of y = mx + b. Therefore, the multiplier
of the x term is the slope. So the slope is +8. Any line that is parallel to this line
must have a slope of 8.
.
So far we know that the slope of a parallel line must be of the form:
.
y = 8x + b

Answer 5

soooooooo what is the answer
if the slope is y=8x+b

Answer 6

wish I could help you >.>

Answer 7

yes

Answer 8

what is the answer tho